Engineering & mechanics
Hydraulic fluid & shaft power
Convert pressure difference and volume flow into fluid power and input power.
A clear answer. Here’s how.
Fluid power is ΔP×Q, so kW=bar×L/min÷600. Input shaft power=fluid power/efficiency; their difference is the inferred loss. Uses a steady, incompressible flow and a supplied overall efficiency from >0–100%. This is an energy balance, not a prediction of pump performance or electric motor current.
See a worked example
Worked example
A fixed demonstration, separate from the values you enter above.
- Pressure difference (bar)
- 100
- Volume flow (L/min)
- 20
- Overall supplied efficiency (%)
- 85
Example result
- Fluid power (kW)
- 3.33333333333
- Input shaft power (kW)
- 3.92156862745
- Power loss (kW)
- 0.588235294118