Science & engineering

Waveform RMS & peak

Compare peak, peak-to-peak and RMS for ideal symmetric periodic waveforms.

Waveform RMS & peak
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A clear answer. Here’s how.

For ideal zero-mean AC waveforms, RMS/peak is 1/√2 for sine, 1 for symmetric square, and 1/√3 for triangle or linear sawtooth. Total RMS with DC offset is √(AC_RMS²+offset²). Peak-to-peak is twice AC peak; extrema are offset ± peak. Duty cycle is 50% for the square wave. This does not generalise to arbitrary measured waveforms.

See a worked example

Worked example

A fixed demonstration, separate from the values you enter above.

AC waveform about its DC offset
Sine
Known AC amplitude
Peak magnitude about DC offset
Known AC amplitude (V)
1
DC offset (V)
0

Example result

AC peak magnitude
1 V
AC peak-to-peak
2 V
AC-only RMS
0.707106781187 V
Total RMS including DC
0.707106781187 V
Waveform maximum
1 V
Waveform minimum
-1 V